The shortest distance between the lines $\frac{x - 3}{2} = \frac{y + 15}{-7} = \frac{z - 9}{5}$ and $\frac{x + 1}{2} = \frac{y - 1}{1} = \frac{z - 9}{-3}$ is

  • A
    $2 \sqrt{3}$
  • B
    $4 \sqrt{3}$
  • C
    $3 \sqrt{6}$
  • D
    $5 \sqrt{6}$

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